3x^2-16x=1344

Solution for 3x^2-16x=1344 equation:

3x^2-16x=1344

We move all terms to the left:

3x^2-16x-(1344)=0

a = 3; b = -16; c = -1344;
Δ = b2-4ac
Δ = -162-4·3·(-1344)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-128}{2*3}=\frac{-112}{6}
=-18+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+128}{2*3}=\frac{144}{6}
=24
$